Class 8 Maths Chapter 7 Cube and Cube Roots

*Class 8 Maths Chapter 7 Cube and Cube Roots STUDY MATERIAL PDF

Syllabus of Class 8 Mathematics

1.Rational Numbers
2.Linear Equations in one variable
3.Understanding Quadrilaterals
4.Practical Geometry
5.Data Handling
6.Squares Square Roots
7.Cube and Cube Roots
8.Comparing Quantities
9.Algebraic Expressions and Identities
10.Visualising Solid Shapes
11.Mensuration
12.Exponents and Powers
13.Direct and Inverse Properties
14.Factorisation
15.Introduction to Graph
16.Playing with Numbers

Revision Notes on Cubes and Cube Roots

Hardy-Ramanujan Number

The number which can be expressed as the sum of two cubes in different ways is said to be a Hardy – Ramanujan number.

1729 = 1728 + 1 = 123 + 13

1729 = 1000 + 729 = 103 + 93

As 1729 is the smallest such type of number so it is called the smallest Hardy-Ramanujan number. There is infinite such type of numbers. Like- 4104 (2, 16; 9, 15), 13832 (18, 20; 2, 24), etc.

Cubes

Cube is a 3-dimensional figure with all equal sides. If one cube has all the equal sides of 1 cm then how many such cubes are needed to make a new cube of side 2 cm?

8 such cubes are needed, and what if we need to make a cube of side 3 cm with the cubes of side 1 cm? The numbers 1, 8, 27 ...etc can be shown below in the cube.

Cubes

These are known as perfect cubes or cube numbers. This shows that we got the cube numbers by multiplying the number three times by itself.

Cubes of Some Natural Numbers

NumberCubesNumbersCubes
11= 11111= 1331
22= 81212= 1728
33= 2713133 = 2197
44= 6414143 = 2744
55= 1251515= 3375
66= 2161616= 4096
77= 34317173 = 4913
88= 5121818= 5832
99= 7291919= 6859
1010= 10002020= 8000

Revision Notes on Cubes and Cube Roots

Hardy-Ramanujan Number

The number which can be expressed as the sum of two cubes in different ways is said to be a Hardy – Ramanujan number.

1729 = 1728 + 1 = 123 + 13

1729 = 1000 + 729 = 103 + 93

As 1729 is the smallest such type of number so it is called the smallest Hardy-Ramanujan number. There is infinite such type of numbers. Like- 4104 (2, 16; 9, 15), 13832 (18, 20; 2, 24), etc.

Cubes

Cube is a 3-dimensional figure with all equal sides. If one cube has all the equal sides of 1 cm then how many such cubes are needed to make a new cube of side 2 cm?

8 such cubes are needed, and what if we need to make a cube of side 3 cm with the cubes of side 1 cm? The numbers 1, 8, 27 ...etc can be shown below in the cube.

Cubes

These are known as perfect cubes or cube numbers. This shows that we got the cube numbers by multiplying the number three times by itself.

Cubes of Some Natural Numbers

NumberCubesNumbersCubes
11= 11111= 1331
22= 81212= 1728
33= 2713133 = 2197
44= 6414143 = 2744
55= 1251515= 3375
66= 2161616= 4096
77= 34317173 = 4913
88= 5121818= 5832
99= 7291919= 6859
1010= 10002020= 8000

This table shows that

  • There are only 10 perfect cubes between 1-1000.

  • The cube of an even number is also even.

  • The cube of an odd number is also an odd number.

One’s digit of the Cubes

 One’s digit of the Cubes of a number having a particular number at the end will always remain same. Let’s see in the following table:

Unit’s digit of numberLast digit of its cube numberExample
11113 = 1331, 213 = 9261, etc.
2823 = 8, 123 = 1728, 323 = 32768, etc.
37133 = 2197, 533 = 148877, etc.
44243 = 13824, 743 = 405224, etc.
55153 = 3375, 253 = 15625, etc.
6663 = 216, 263 = 17576,etc.
73173 = 4913, 373 = 50653,etc.
8283 = 512, 183 = 5832, etc.
99193 = 6859, 393 = 59319, etc.
1020103 = 1000, 203 = 8000, etc.

Some Interesting Patterns

1. Adding Consecutive Odd Numbers

Adding Consecutive Odd Numbers

This shows that if we add the consecutive odd numbers then we get the cube of the next number.

2. Cubes and their Prime Factors

Prime factorization of a number is done by finding the prime factors of the number and then pairing it in the group of three. If all the prime factors are in the pair of three then the number is a perfect cube.

Example

Calculate the cube root of 13824 by using prime factorization method.

Solution

First of all write the prime factors of the given number then pair them in the group of three.

Prime factors

Since all the factors are in the pair of three the number 13824 is a perfect cube.

Smallest Multiple that is a Perfect Cube

As we have seen that the group of three prime factors makes a number perfect cube, so to make a number perfect cube we need to multiply it with the smallest multiple of that number.

Example

Check whether 1188 is a perfect cube or not. If not then which smallest natural number should be multiplied to 1188 to make it a perfect cube?

Solution

1188 = 2 × 2 × 3 × 3 × 3 × 11

This shows that the prime numbers 2 and 11 are not in the groups of three. So, 1188 is not a perfect cube

To make it a perfect cube we need to multiply it with 2 × 11 × 11 = 242, so, it will make the pair of 2, 3 and 11.

 Hence the smallest natural number by which 1188 should be multiplied to make it a perfect cube is 242.

And the resulting perfect cube is 1188 × 242 = 287496 ( = 663).

Cube Roots

Finding cube root is the inverse operation of finding the cube.

If 33 =27 then cube root of 27 is 3.

We write it as ∛27 = 3

Symbol of the Cube Root

Symbol of the Cube Root

Some of the cube roots are:

StatementInferenceStatementInference
13 = 1∛1 = 16= 216∛216 = ∛6= 6
2= 8∛8 = ∛2= 27= 343∛343 = ∛7= 7
3= 27∛27 = ∛33 = 38= 512∛512 = ∛8= 8
4= 64∛64 = ∛4= 49= 729∛729 = ∛9= 9
5= 125∛125 = ∛5= 510= 1000∛1000 = ∛10= 10

Method of finding a Cube Root

There are two methods of finding a cube root

1. Prime Factorization Method

Step 1: Write the prime factors of the given number.

Step 2: Make the pair of three if possible.

Step 3: Then replace them with a single digit.

Step 4: Multiply these single digits to find the cube root.

Example

Find the cube root of 15625 by the prime factorization method.

prime factorization

2. Estimation Method

This method is based on the estimation. Let's take the above example.

Step 1: If 15625 is the number then make the group of three digits starting from the right.

15 625

Step2: Here 625 is the first group which tells us the unit’s digit of the cube root. As the number is ending with 5 and we know that 5 comes at the unit’s place of a number only when its cube root ends in 5.

So the unit place is 5.

Step 3: Now take the other group, i.e., 15. Cube of 2 is 8 and a cube of 3 is 27. 15 lie between 8 and 27. The number which is smaller among 2 and 3 is 2. The one’s place of 2 is 2 itself. Take 2 as ten’s place of the cube root of 15625. Thus, 


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